Like function with Ajax / PHP / jQuery

1 week ago, i decided to start adding AJAX and more jquery to my Website. I think, the "combination" of PHP / Jquery / AJAX is the best thing ever.

Now i want to create a "like - system" in my community board. I did something similar already:

$(function(){
    $('.action-button.like').click(function(){
        //ajax part
        var articleId = $('.article-Id').html();
        $.ajax({
            type: "GET",
            async: true,
            url: '/wiki/parts/likeArticle.php',
            data:  { 'articleId': articleId },
            //change button
            success: function (msg){ 
                $('.action-button.like span').fadeOut(400);
            },
            error: function (err)
            { alert(err.responseText)}
        });
    }); 
});

as you can see, the button / element disappears after a click() on it. PHP data: the .php file "inserts the like" into the database ...

So - this works great ! Back to my question: After an user likes the post, i want to display a container with all users, which did this before.

I'm asking this, because i know how to do this / I have an Idea how i can realise my little project, but i dont know, if this is the propper way :)

My solution:

in $.ajax: I want to create a function on "success:" (and a new .php file, which loads all users / "likers") the function uses .load() and loads the file, so everything should be done right, shouldn't it ?

I hope you understand my problem, Greets :)